2[3b-1]=40

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Solution for 2[3b-1]=40 equation: 


Simplifying
2[3b + -1] = 40

Reorder the terms:
2[-1 + 3b] = 40
[-1 * 2 + 3b * 2] = 40
[-2 + 6b] = 40

Solving
-2 + 6b = 40

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 6b = 40 + 2

Combine like terms: -2 + 2 = 0
0 + 6b = 40 + 2
6b = 40 + 2

Combine like terms: 40 + 2 = 42
6b = 42

Divide each side by '6'.
b = 7

Simplifying
b = 7

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